jQuery post数据至ashx

2018-06-22 07:34:53来源：未知阅读 ()

今天给大家分享一个小功能，在jQuery环境中，Post data to ashx进行数据交互。

参考下面代码示例：

$.ajax({
                     url: '<%= ResolveUrl("~/Handlers/xxx.ashx") %>',
                            dataType: "json",
                            type: "POST",
                            contentType: "application/json; charset=utf-8",
                            data: JSON.stringify({
                                top: 10,
                                term: request.term
                            }),
                            success: function (data) {
                                //...
                            }
                        });

Source Code

jQuery的Post值是使用type: "POST"，上传的数据类型为contentType: "application/json; charset=utf-8"。

从代码示例中，它有2个参考需要上传，top，term。

为了更好在ashx能接收，我们写一个model:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;

/// <summary>
/// Summary description for Param
/// </summary>
namespace Insus.NET
{
    public class Param
    {
        private int _top;
        public int Top
        {
            get { return _top; }
            set { _top = value; }
        }


        private string _term;

        public string Term
        {
            get { return _term; }
            set { _term = value; }
        }
    }
}

Source Code

在ashx处理程序中，我们可以同下面这样接收Post过来的数据：

public void ProcessRequest(HttpContext context)
        {
            context.Response.ContentType = "application/json";
            context.Response.ContentEncoding = Encoding.UTF8;

            Stream inputStream = context.Request.InputStream;
            Encoding encoding = context.Request.ContentEncoding;
            StreamReader streamReader = new StreamReader(inputStream, encoding);

            string strJson = streamReader.ReadToEnd();

            Param p = JsonConvert.DeserializeObject<Param>(strJson);

            int top = Convert.ToInt32(p.Top);
            string term = p.Term;

           
            //var result = ...
            //context.Response.Write(result.ToJson());
        }