函数式编程

def test():
    return n+1

def text(n) :
    print(n)
def test(name)
    print(name)

text(test(sumcet))

sumcet
None

s = [1, 2, 3, 4, 5]


def reduce(li1):
    return li1 - 1#减操作


def add(li2):
    return li2 + 1#加操作


def invo(li3):
    return li3 * li3#幂运算

#map函数的内部实现
def map_ex(func, li):
    b = []
    for a in s:
        b.append(func(a))
    return b


print(map_ex(add, s))#map_ex(add,s)将获取add函数的地址
print(map_ex(reduce, s))
print(map_ex(invo, s))
print('********************')
#利用map函数实现同样功能。
print(list(map(lambda x: x + 1, s)))#lambda匿名函数，s必须是可迭代对象，与上面结果进行对比
print(list(map(lambda x: x - 1, s)))
print(list(map(lambda x: x * x, s)))

[2, 3, 4, 5, 6]
[0, 1, 2, 3, 4]
[1, 4, 9, 16, 25]
********************
[2, 3, 4, 5, 6]
[0, 1, 2, 3, 4]
[1, 4, 9, 16, 25]

name = ['bbu', 'sumcet', 'loVe']


def eng(s):
    s1 = s[0:1].upper() + s[1:].lower()
    return s1


print(list(map(eng, name)))

['Bbu', 'Sumcet', 'Love']

s = ['a_bbu', 'b_bbu', 'c_bbu']
a = filter(lambda x: x.startswith('b'), s)
print(list(a))

['b_bbu']

from functools import reduce

s = [1, 2, 3, 4, 5, 6]
a = reduce(lambda x, y: x * y, s, 1)
print(a)　

720