c++实现对输入数组进行快速排序

2018-06-17 22:29:03来源:未知 阅读 ()

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#include "stdafx.h"
#include <iostream>
#include <string>
#include <vector>
using namespace std;
void quickSort(vector<int> &a, int, int);
void swap(int &a, int&b);
vector<string> split(string s, string seperator);

int main() {
    string str;
    cout << "please input your array: " << endl;
    getline(cin, str);
    vector<string> strs = split(str, " ");
    cout << "The original array is " << endl;
    for (unsigned int i = 0; i < strs.size(); i++) {
        cout << strs[i] << " ";
    }
    cout << endl;
    vector<int> array(strs.size());
    for (unsigned int i = 0; i < strs.size(); i++) {
        array[i] = atoi(strs[i].c_str());
    }
    int len = array.size();
    cout << "The ordered array is " << endl;
    quickSort(array, 0, len-1);
    for (int i = 0; i < len; i++) {
        cout << array[i] << " ";
    }
    cout << endl;
    system("pause");
    return 0;
}
void quickSort(vector<int> &a, int start, int base) {
    if (start >= base) {
        return;
    }
    int i = start, j = start;
    int temp = a[base];
    for (;j<base;j++) {
        if (a[j]<=temp) {
            swap(a[i], a[j]);
            i++;
        }
    }
    if (a[i] > a[base]) {
        swap(a[i], a[base]);
    }
    quickSort(a, start, i - 1);
    quickSort(a, i + 1, base);
}
void swap(int &a, int&b) {
    if (a == b) {
    }
    else {
        a = a + b;
        b = a - b;
        a = a - b;
    }
    
}
vector<string> split(string s, const string pattern) {
    string::size_type pos;
    vector<string> result;
    s += pattern;
    unsigned int size = s.size();
    for (unsigned int i = 0; i < size; i++) {
        pos = s.find(pattern, i);
        if (pos < size) {
            string str = s.substr(i, pos - i);
            if (!str.empty()){
                result.push_back(str);
            }
            i = pos + pattern.size() - 1;

        }
    }
    return result;
}

 

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