178. Rank Scores solution
2018-06-18 00:59:07来源:未知 阅读 ()
problem:
Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" between ranks.
+----+-------+ | Id | Score | +----+-------+ | 1 | 3.50 | | 2 | 3.65 | | 3 | 4.00 | | 4 | 3.85 | | 5 | 4.00 | | 6 | 3.65 | +----+-------+
For example, given the above Scores
table, your query should generate the following report (order by highest score):
+-------+------+ | Score | Rank | +-------+------+ | 4.00 | 1 | | 4.00 | 1 | | 3.85 | 2 | | 3.65 | 3 | | 3.65 | 3 | | 3.50 | 4 | +-------+------+
Select Scores.Score, count(ranking.Score) as Rank
from Scores,
(select distinct score from Scores) as ranking
where Scores.Score<=ranking.Score
group by Scores.Id
order by Scores.score Desc;
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- MySQL(五) 2018-06-18
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