Delphi 汇编例子1(求和的比较)

2008-04-09 04:26:56来源:互联网 阅读 ()

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简单的,你现在就可以试一试:)。

-----以前学汇编的时候做的测试。第一个程序只是给您个印象,后面还有一个帖子,在详细说说。

unit Unit1;

interface

uses
Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
Dialogs, StdCtrls, ExtCtrls;

type
TForm1 = class(TForm)
Shape1: TShape;
Label1: TLabel;
Label2: TLabel;
Label3: TLabel;
Button1: TButton;
Button2: TButton;
Label4: TLabel;
Label5: TLabel;
Label6: TLabel;
Button3: TButton;
procedure Button1Click(Sender: TObject);
procedure Button2Click(Sender: TObject);
//procedure Button3Click(Sender: TObject);
//procedure BtCalcuClick(sender: TObject);
private
{ Private declarations }
public
{ Public declarations }
end;

var
Form1: TForm1;
function Sum1(X,Y:integer):integer;
function Sum2(X,Y:integer):integer;stdcall;
function Sum3(var X,Y:integer):integer;stdcall;
implementation

{$R *.dfm}

procedure TForm1.Button1Click(Sender: TObject);
var
i,j:integer;
begin
label1.Caption:=inttostr(sum1(2,3));
label2.Caption:=inttostr(sum2(2,3));
i:=2;
j:=3;
label3.Caption:=inttostr(sum1(i,j));
end;

//delphi程序求和
function Sum1(X,Y:integer):integer;
begin
result:=X Y;
end;

//汇编求和1---
function Sum2(X,Y:integer):integer;stdcall;
begin
asm
mov eax,X
add eax,Y
mov @result,eax
end;
end;
//汇编求和2---
function Sum3(var X,Y:integer):integer;stdcall;
begin
asm
mov eax,X
mov eax,[eax]
mov edx,Y
add eax,[edx]
mov @result,eax
end;
end;


procedure TForm1.Button2Click(Sender: TObject);
begin
close;
end;

{procedure TForm1.Button3Click(Sender: TObject);
var
QuitFlag:Boolean;
OutBufPtr:Word;
begin
asm
mov al,QuitFlag
mov bx,OutBufPtr
end;
end;}

end.

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