VB编程破解Windows屏幕保护密码

2008-02-23 07:02:41来源:互联网 阅读 ()

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大家都知道,屏幕保护密码最多为16个字符。微软内置了16字节的密钥:48 EE 76 1D 67 69 A1 1B 7A 8C 47 F8 54 95 97 5F。Windows便用上述密钥加密你输入的密码。其加密过程为:首先将你输入的密码字符逐位转换为其16进制的ASCⅡ码值(小写字母先转为大写字母),再依次与对应密钥逐位进行异或运算,把所得16进制值的每一位当作字符,转换为其16进制ASCII码,并在其尾加上00作为结束标志,存入注册表HKEY_CURRENT_USER\Control Panel\desktop下的二进制键ScreenSave_Data中。

  懂得其加密原理后,便不难编程破解我的屏幕保护密码(即上网密码)了。本人用VB6.0编制了一读取注册表中ScrrenSave_Data值的函数GetBinaryValue(Entry As String),读出其值为31 43 41 33 33 43 35 35 33 34 32 31 00,去掉其结束标志00,把余下字节转换为对应的ASCII字符,并把每两个字符组成一16进制数:1C A3 3C 55 34 21,显然,密码为6位,将其与前6字节密钥逐一异或后便得出密码的ASCII码(16进制值):54 4D 4A 48 53 48,对应的密码明文为TMJHSH,破解成功!用它拔号一试,呵,立刻传来Modem欢快的叫声。

  附VB源程序:(程序中使用了窗体Form1,文本框Text1,命令按钮Command1)

  1、窗体代码:

  Option Explicit

  Dim Cryptograph As String

  Dim i As Integer

  Dim j As Integer

  Dim k As Integer

  Dim CryptographStr(32) As Integer

  Dim PWstr As String

  Dim PassWord As String

  Private Sub Command1_Click()

  PWstr = ""

  PassWord = ""

  Text1.Text =""

  Cryptograph = GetBinaryValue("ScreenSave_Data")

  k = Len(Cryptograph)

  For j = 1 To k - 1

   For i = 32 To 126

   If Mid(Cryptograph, j, 1) = Chr(i) Then

   CryptographStr(j) = i

   End If

   Next i

  Next j

  i = (k - 1) / 2 '密码位数为(h-1)/2,根据位数选择解密过程。

  Select Case i

  Case 16

   GoTo 16

  Case 15

   GoTo 15

  Case 14

   GoTo 14

  Case 13

   GoTo 13

  Case 12

   GoTo 12

  Case 11

   GoTo 11

  Case 10

   GoTo 10

  Case 9

   GoTo 9

  Case 8

   GoTo 8

  Case 7

   GoTo 7

  Case 6

   GoTo 6

  Case 5

   GoTo 5

  Case 4

   GoTo 4

  Case 3

   GoTo 3

  Case 2

   GoTo 2

  Case 1

   GoTo 1

  Case Else

   End

  End Select

  16: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(31)) & Chr(CryptographStr(32))) Xor &H5F)

  15: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(29)) & Chr(CryptographStr(30))) Xor &H97)

  14: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(27)) & Chr(CryptographStr(28))) Xor &H95)

  13: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(25)) & Chr(CryptographStr(26))) Xor &H54)

  12: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(23)) & Chr(CryptographStr(24))) Xor &HF8)

  11: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(21)) & Chr(CryptographStr(22))) Xor &H47)

  10: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(19)) & Chr(CryptographStr(20))) Xor &H8C)

  9: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(17)) & Chr(CryptographStr(18))) Xor &H7A)

  8: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(15)) & Chr(CryptographStr(16))) Xor &H1B)

  7: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(13)) & Chr(CryptographStr(14))) Xor &HA1)

  6: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(11)) & Chr(CryptographStr(12))) Xor &H69)

  5: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(9)) & Chr(CryptographStr(10))) Xor &H67)

  4: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(7)) & Chr(CryptographStr(8))) Xor &H1D)

  3: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(5)) & Chr(CryptographStr(6))) Xor &H76)

  2: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(3)) & Chr(CryptographStr(4))) Xor &HEE)

  1: PWstr = PWstr & Chr(("&H" & Chr(CryptographStr(1)) & Chr(CryptographStr(2))) Xor &H48)

  For i = i To 1 Step -1 '所得PWstr的值为密码的倒序列,将其倒置便得出密码。

   PassWord = PassWord & Mid(PWstr, i, 1)

  Next i

  Text1.Text = PassWord '在文本框内显示密码。

  End Sub

  2、模块代码:

  Option Explicit

  Const ERROR_SUCCESS = 0&

  Const ERROR_BADDB = 1009&

  Const ERROR_BADKEY = 1010&

  Const REG_EXPAND_SZ = 2&

  Const REG_BINARY = 3&

  Const KEY_QUERY_VALUE = &H1&

  Const KEY_ENUMERATE_SUB_KEYS = &H8&

  Const KEY_NOTIFY = &H10&

  Const READ_CONTROL = &H20000

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