在Java8里创建Stream的几种方法
2018-07-20 来源:open-open
创建Stream的方法共有5种,分别为如下
import java.math.BigInteger; import java.util.ArrayList; import java.util.Arrays; import java.util.List; import java.util.regex.Pattern; import java.util.stream.Stream; /** * * @author Kangjun Ways of Creating a Stream in Java 8 */ public class StreamDemo { public static void main(String[] args) { arraysStream(); collectionStream(); generate(); iterateStream(); populaStream(); } //From Arrays public static void arraysStream() { String[] arr = {"program", "creek", "program", "creek", "java", "web", "program"}; Stream<String> stream = Stream.of(arr); System.out.println(Arrays.toString(arr)); } //From Collections public static void collectionStream() { List<String> list = new ArrayList<>(); list.add("Java"); list.add("python"); list.add("c++"); list.add("c"); list.add("lisp"); Stream<String> stream = list.stream().filter(p -> p.length() > 3); String[] arr = stream.toArray(String[]::new); System.out.println(Arrays.toString(arr)); } //Use Stream.generate() public static void generate() { Stream<String> stream = Stream.generate(() -> "test").limit(10); String[] strArr = stream.toArray(String[]::new); System.out.println(Arrays.toString(strArr)); } //Use Stream.iterate() public static void iterateStream() { Stream<BigInteger> bigIntStream = Stream.iterate(BigInteger.ZERO, n -> n.add(BigInteger.TEN)).limit(10); BigInteger[] bigIntArr = bigIntStream.toArray(BigInteger[]::new); System.out.println(Arrays.toString(bigIntArr)); } // From Popular APIs public static void populaStream() { String sentence = "Program creek is a Java site."; Stream<String> wordStream = Pattern.compile("\\W").splitAsStream(sentence); String[] wordArr = wordStream.toArray(String[]::new); System.out.println(Arrays.toString(wordArr)); } }
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