Python备份sqlserver中的视图、函数、存储过程
2018-07-20 来源:open-open
[Python]代码
#!/usr/bin/python # coding=gbk import os import re import time import datetime import operator import pyodbc import sys """ backup procedure,view,function """ def ado_cmd(src, sql): db = pyodbc.connect(src) cursor = db.cursor() cursor.execute(sql) db.commit() db.close() def ado_sel(src, sql): db = pyodbc.connect(src) cursor = db.cursor() cursor.execute(sql) ds = cursor.fetchall() db.close() return ds def getprocedure(src, pname): sql = "EXEC Sp_HelpText '" + pname + "';" ds = ado_sel(src, sql) text = '' index = 0 try: for dr in ds: #print(str(dr[0])) text = text + str(dr[0]) text = text.replace("\r\n", "") + "\n" index = index + 1 except Exception as e: print("查询存储过程出错:" + pname + " [line:"+str(index)+"] ") print(e) return text if __name__ == '__main__': src = 'DRIVER={SQL Server};SERVER=服务器;DATABASE=数据库;UID=用户名;PWD=密码' # p procedure; v view; fn function sql = "SELECT [name],[type] FROM sysobjects WHERE type IN('p','v','fn') order by name" #src = 'DSN=sampledb;UID=dba;pwd=sql' now = datetime.datetime.now() path = now.strftime('%Y-%m-%d') if os.path.exists(path): for i in range(98,122): new_path = path + "_" + chr(i) if not os.path.exists(new_path): path = new_path break else: print(new_path + '已存在') os.makedirs(path) #创建新文件夹 sv = "View" sp = "Prodecure" sfn = "Function" os.makedirs(path + '/' + sv) os.makedirs(path + '/' + sp) os.makedirs(path + '/' + sfn) ds = ado_sel(src, sql) i_count = len(ds) print("count=" + str(i_count)) for dr in ds: p2 = "" pname = str(dr[0]) typ = str(dr[1]) typ = typ.strip() if typ == "V" : p2 = sv elif typ == "P" : p2 = sp elif typ == "FN" : p2 = sfn print(typ + ", " + p2 + ", " + pname) text = getprocedure(src, pname) filename = pname + ".sql" file1 = open(path + "/" + p2 + "/" + filename, "w") file1.write(text + "\n") file1.close
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